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Deffense [45]
3 years ago
10

115km×10=how many hm

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

1km=10hm (hecto meters=100m)

115km=115×10=1150hm

If you have 1150km, then you get 11500hm.

Just take km and multiply by 10 to get hm

andrezito [222]3 years ago
6 0
This answer to this question is 1150 km
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Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb
jonny [76]

Answer:  The answer is 400  blue marbles.


Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,

and number of blue marbles is

n_b=560-364=196.

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.

Thus, 400 blue marbles need to be added to the bag.


5 0
3 years ago
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How do I log on the Roblox
Eva8 [605]

Answer:

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6 0
4 years ago
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I'd really appreciate your help, please no joke answers
Lerok [7]

Answer:

d= 2√10

Step-by-step explanation:

y= 3x - 5

3x - y - 5=0

d= | 3* 7 +(-1) * (-4) + (+5) |

     ________________

       \sqrt{3^{2} } + (-1)^{2}

d = | 20 | / \sqrt{10}

d = 20 / \sqrt{10}

d = 2\sqrt{10}

3 0
3 years ago
Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
3 years ago
1 L of a 78% acid solution was mixed with 6 L of a 64% acid solution. Find the concentration of the new mixture.
JulijaS [17]

The first solution contributes 0.78*1 = 0.78 L of acid.

The second contributes 0.64*6 = 3.84 L of acid.

There will be 7 L total of the new solution, and 3.84 + 0.78 = 4.62 total L of acid in it. So the new solution has a concentration of 4.62/7 = 0.66, or about 66%.

8 0
3 years ago
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