Entire the solution as s completely simplified fraction: <br> 8/22 + 5/22 + (-7/-22)

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

so

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

3 years ago

in 4 minutes Liaa can type 140 words. If she has an essay taht is 700 words long , about how long will it take Liana to type it

Zanzabum

Answer: Lol your in collage I don't believe it anyway the answer is 20 min on the dot

6 0

2 years ago

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet

Natali5045456 [20]

Complete Question

A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet from the ground and he catches it when it is four feet from the ground,How long is the ball in the air?

Answer:

$t\approx 0.1s$

Step-by-step explanation:

From the question we are told that

Initial velocity $V_0= 18 ft/s$

Initial Height $h_1=5feet$

Final Height $h_2=4feet$

Generally the Newtons equation for motion is mathematically given by

$V^2 = U^2 + 2as$

Where

$s=h_2-h_1\\s=4-5\\s=-1ft$

And

$a=g=>9.81\\a=32.2ft/s^2$

Therefore

$V^2 = (18)^2 + 2(-32.2)(-1)$

$V^2 = 388.4$

$V =19.70786645\\V=19.71ft/s$

Generally the equation for Time is mathematically Given as

$t=\frac{V-U}{a}$

$t=\frac{19.71-18}{32.2}$

$t=0.05310559006$

$t\approx 0.1s$

Therefore the time spent on air by the ball is

$t=0.05310559006s$

4 0

3 years ago

Brandon and Jerry like to play video games. Brandon has vvv video games, and Jerry has 292929 video games. Together they have a

lianna [129]

Answer:

444,444

Step-by-step explanation:

total amount=737373

jerry=292929

Brandon=unknown

To figure the amount of video games Brandon has, we have to subtract the amount of both he and his friend altogether amount with Jerry's current amount of video games.

737,373-292,929=444,444

So, by subtracting the two, the answer would be 444,444.

Brandons total amount of video games:444,444

5 0

2 years ago

How do you change y=x^2-10x-6 into vertex form

In-s [12.5K]

Converting to vertex form is actually pretty simple so I think you might find something to help you out here. :)

https://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html

3 0

3 years ago

Entire the solution as s completely simplified fraction: 8/22 + 5/22 + (-7/-22)