Answer:
more than one safeguard may be necessary.
Explanation:
The conceptual framework can be used to developed as well as construct through a process of the qualitative analysis. The approach includes the in the frameworks for identifying and evaluating the threats to compliance with the rules.
But since the rules formed cannot always address all the circumstances, the Code includes to evaluate the threats to the compliance of more than one safeguards that are necessary.
Answer:
The answer is "Referential integrity".
Explanation:
This relates to one aspect of data integrity. Data across multiple tables are linked via relationships. In view of the distinct customer & invoice tables, each invoice table should have the primary key specified throughout the Customer table, for instance. Whenever the invoice table contains a customer ID reference. This ID including its customer will be only a table of the customer.
Answer:
- Code is in JAVA language. As there is no user input the logic is straightforward.
- Below is the code along with a detailed explanation of the logic.
- The class name is Print main save as file as the main class.
Explanation:
Program:-
public class Main{
public static void main(String args[]){
/* There are two for loops...
* First for loop runs from i=1 to i=9
* Second for loop runs from j=1 to j=i.
*
*/
for(int i=1;i<=9;i++){
for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i
/*Prints I and j next to each other*/
System.out.println(i+""+j);
}//for loop of j ends here
}// for loop of I ends here
}
}
Answer:
Look up Charles Babbage. He built a machine that is viewed as the predecessor of the modern computer.
Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
