The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Answer:
8
Step-by-step explanation:
5(3-1)-2
5(2)-2
10-2
8
Step-by-step explanation:
A + 2 ÷ (-24) = -4
A - 1/12 = -4
A = -4 + 1/12
A = -48/12 + 1/12
A = -47/12
A ≈ -3,91
Answer:
1296
Step-by-step explanation:
(1/6)^-4
6^4/1
1296/1
1296
You ran 4.64 km altogether
Step-by-step explanation:
If you go for a run on Monday and manage to run 2.32 km and the on Tuesday you run the same distance, then that would be another 2.32 km ran on Tuesday. We can then add these two together to figure out your Total distance ran altogether in those 2 days.
