Longitud = L Ancho = A
2A + 2L = 54
L = 2A Sustituir este valor por L en la primera ecuación:
2A + 2(2A) = 54
2A + 4A = 54
6A = 54
A = 9
También porque L = 2A,
L = 2(9) = 18
The perimeter of a rectangle is given by the following formula: P = 2W + 2L
To solve this formula for W, the goal is to isolate this variable to one side of the equation such that the width of the rectangle (W) can be solved when given its perimeter (P) and length (L).
P = 2W + 2L
subtract 2L from both sides of the equation
P - 2L = 2W + 2L - 2L
P - 2L = 2W
divide both sides of the equation by 2
(P - 2L)/2 = (2W)/2
(P - 2L)/2 = (2/2)W
(P - 2L)/2 = (1)W
(P - 2L)/2 = W
Thus, given that the perimeter (P) of a rectangle is defined by P = 2W + 2L ,
then its width (W) is given by <span>W = (P - 2L)/2</span>
First you have to change each one into a decimal.
10% = 0.10
1/9 = 0.11
So the answer has to be between 0.10 and 0.11.
A is more than 0.11.
B is more than 0.11.
C is between 0.10 and 0.11.
D is less than 0.10.
The answer is C. 0.108.
