Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Given that a unshaded rectangle is inscribed in a shaded circle.
- Diameter of the circle d = 13m
- Radius r = d/2 = 13m/2 = 6.5m
- Dimension of length of the rectangle l = 12m
- Dimension of width of the rectangle w = 5m
- Area of the shaded region As = ?
First we calculate the area of the shaded circle.
A = πr² = π × ( 6.5m )²
A = 132.665m²
Area of the shaded circle is 132.665m².
Area of the unshaded rectangle will be;
A = l × w
A = 12m × 5m
A = 60m²
Area of the unshaded rectangle is 60m².
Now, area of the shaded region will be;
= Area of the shaded circle - Area of the unshaded rectangle
= 132.665m² - 60m²
= 132.665m² - 60m²
= 72.67m²
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
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{0, 2, 1/2}
f(h) = 0 when any set of parenthesis equals zero
1. h = 0
2. h - 2 = 0
add 2
h = 2
3. 2h - 1 = 0
Add 1
2h = 1
divide by 2
h = 1/2
Answer:
B. Angle E=43
Step-by-step explanation:
Angles DEF are = to 73 degrees
73-43=30/2=15
15+15+43=73