Hello there!
The answer is C.
I will explain to you how I came to this answer.
•First of all, I counted the turning points. There are two, so that means this polynomial function has THREE roots. (# of turning points+1=number of roots.)
•Next, look to see how many times the function crosses the x-axis. This is the number of REAL solutions. In this case, there is one point at which the f(x) is crossing the x-axis so there is one real solution.
•Since there is one real solution there has to be 2 imaginary roots. (Total # of solutions-real solutions=imaginary solutions)
NOTE: the turning points are where the increasing intervals change to decreasing and the decreasing change to increasing. The first derivative at these points is 0.
I hope this helps!
Best wishes~
-HuronGirl
Answer:
77
Step-by-step explanation:
Plug in:
F(4) = (4)3 + 2(4)2 + 1
F(4) = 12 + (8)^2 + 1
F(4) = 12 + 64 + 1
F(4) = 77
(assuming 2x2 = 2x squared)
A is -12/15 (4/5)
B is 35/12
C is 56
D is 8/15
Sorry if any of these are wrong.
To check them, turn any mixed number into an improper fraction. Then, multiply by the reciprocal. Ex: 4/0 divided by 1/3
X reciprocal- 4/0 times 3/1
