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mariarad [96]
4 years ago
11

You are paid $78 for 6 1/2 hours of work. What is your rate of pay?

Mathematics
2 answers:
____ [38]4 years ago
7 0
Pay for 6½ hours = $78
Pay for an hour = $78/6.5
= $12

So, I get paid $12 for an hour.
yuradex [85]4 years ago
4 0
6 1/2 hours = 6.5 hours
78/6.5=12
My rate of pay is 12$ per hour
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emmasim [6.3K]

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A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.
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6 0
3 years ago
A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
melomori [17]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

p_v =P(t_{(13)}  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=24 represent the sample mean

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for the average speed is lower than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=14-1=13  

Since is a one side test the p value would be:  

p_v =P(t_{(13)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

7 0
3 years ago
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