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dimaraw [331]
3 years ago
6

2. Find the surface area of the solid

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

C. SA = 148.8 ft

Step-by-step explanation:

3.1×8×6= 148.8

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Paladinen [302]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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£70 is divided between Natasha, Richard & Stephen so that Natasha gets twice as much as Richard, and Richard gets three time
Mekhanik [1.2K]

Answer:

  £42

Step-by-step explanation:

The ratio of Richard's amount to Stephen's amount is ...

  R : S = 3 : 1

The ratio of Natasha's amount to Richard's amount is ...

  N : R = 2 : 1 = 6 : 3

Then the ratio of all three amounts is ...

  N : R : S = 6 : 3 : 1

The proportion of the total that Natasha gets is ...

  6/(6+3+1) = 6/10

so she gets ...

  (6/10)×£70 = £42

Natasha gets £42.

5 0
3 years ago
How to solve 76×327 step by step
hram777 [196]

Here's a method that takes advantage of the values of these particular numbers.

... 76 = 80 - 4

so

... 76 × 327 = (80 -4)×327

... = 80×327 - 4×327

Repeated doubling will give us values that are 2, 4, and 8 times 327.

... 2×327 = 327+327 = 654

... 2×654 = 4×327 = 654+654 = 1308 . . . . we'll use this later

... 2×1308 = 8×327 = 2616

We want 80×327, so we can add a zero to the end of this last:

... 80×327 = 26160

Now, we can subtract 4×327 to get 76×327

... 80×327 - 4×327 = 26160 -1308 = 24852 = 76×327

_____

More conventionally, you would multiply every digit of one number by every digit of the other and add the products according to their respective place values.

327 × 076 = (3×0)×10000 + (3×7 +2×0)×1000 +(3×6 +7×0 +2×7)×100 +(2×6 +7×7)×10 +(7×6)×1

... = 0 +21,000 +3,200 + 610 +42

... = 24,852

Note the pattern of partial products here. This is a method taught to/by practitioners of Vedic mathematics, and can be done in your head. At most, you would write down the partial product sums 21, 32, 61, and 42 to keep from having to carry more than one number in your head at a time.

5 0
3 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
3 years ago
ron drew a quadrilateral with 4 right angles and 4 sides with the same length what figure díd he drew
vladimir1956 [14]
Ron drew a parallelogram.
6 0
3 years ago
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