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3 years ago

Ans please quickly & correctly question in the photo

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

Answer:

A Standard Drink

Step-by-step explanation:

1/3 = 0.33

1 is 33% of 3 bigger than any other one.

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Pls help asap, ill give brainiest

zloy xaker [14]

The answer is D

If this helped a brainliest would be appreciated!

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2 years ago

Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro

tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation

n=2700 represent the random sample taken

X represent the people in England who are deficient in Vitamin D

$\hat p=0.2$ estimated proportion of England people who are deficient in Vitamin D

$\alpha=0.02$ represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And replacing into the confidence interval formula we got:

$0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182$

$0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218$

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0

3 years ago

Paws at play made a total of $1234 grooming 22 dogs. Paws at Play charges $43 to groom each small dog and $75 for each large dog

vitfil [10]

Answer:

Answer (a):

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Answer (b)

9 large dogs.

Step-by-step explanation:

Paws at Play made a total of $1234 grooming 22 dogs.

Paws at Play charges $43 to groom each small dog and;

$75 for each large dog.

Let the number of small dogs be 's'

And the number of large dogs be 'l'

A system of equations will be:

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;

43s + 43l = 946 ... (i)

43s + 75l = 1234 ... (ii)

Subtracting (i) from (ii) we get;

32l = 288 , l = $\frac{288}{32}$ = 9

So there are 9 large dogs.

8 0

3 years ago

......ssssssssssssssssssssssssssssssssssssshhhhhh

Darina [25.2K]

Hey there! I'm happy to help!

Step 2 is incorrect. She added 4 and 2 first, but you are supposed to multiply and divide first. Then she multiplied 6 and 6, which is 36. Then she divided 36 and 2, which is 18, and then she subtracted 7, giving her 11. Step 2 is what threw the whole thing off.

Here is what Sandy should have done.

STEP 1: 6·4+2÷2-7

STEP 2: 24+1-7

STEP 3: 25-7

STEP 4: 18

I hope that this helps! Have a wonderful day! :D

3 0

3 years ago

Read 2 more answers

I am very sorry because this is off-topic but is it normal to have 840/500 points? for ranking?

hichkok12 [17]

Answer:

i think so

Step-by-step explanation:

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2 years ago