Ans please quickly & correctly question in the photo
1 answer:
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Yuck, trig. I'm doing college trig at this very moment.
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"
Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.
Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)
so we are very close to (-y, -x).
The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.
ANSWER:
"<span>a 90 clockwise rotation about the origin and a reflection over the y-axis</span>"