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Vikentia [17]
3 years ago
12

Which polynomial identity will prove that 117 = 125 − 8?

Mathematics
2 answers:
Levart [38]3 years ago
7 0
The answer is Sum of cubes :)
777dan777 [17]3 years ago
4 0

Answer:

Difference of cubes.

Step-by-step explanation:

We are asked to find the identify that will prove that 117=125-8.

Polynomial identities are equations that are true and have general applications in our algebra work.

We can see that 125 equals 5^3 and 8 equals 2^3. So polynomial identity used in our given problem is difference of cubes.

Difference of cubes: a^3-b^3=(a-b)(a^2+ab+b^2)

Let us prove that 117=125-8.

We can write right hand side of our given equation as:  

5^3-2^3=(5-2)(5^2+5\times 2+2^2)

125-8=(3)(25+10+4)

117=(3)(39)

117=117  

We can see that left hand side of our equation is equal to right hand side of equation. Hence, proved that difference of cubes will prove our equation equal.


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4 years ago
A supervisor records the repair cost for 22 randomly selected VCRs. A sample mean of $75.50 and standard deviation of $18.07 are
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Answer:

<em>  The 99% confidence interval for the mean repair cost for the VCRs</em>

(65.801, 85.199)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Mean of the sample(x⁻) = $75.50

Given the standard deviation of the sample (S) =  $18.07

Given the size of the sample 'n' = 22

Degrees of freedom = n-1 =22-1 =21

critical value t₍₀.₀₁, ₂₁₎ = 2.5176

<em> The 99% confidence interval for the mean repair cost for the VCRs</em>

(x^{-} - t_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +t_{0.01} \frac{S.D}{\sqrt{n} })

(75.50 - 2.5176 \frac{18.07}{\sqrt{22} } , 75.50 +2.5176 \frac{18.07}{\sqrt{22} })

( 75.50 - 9.699 , 75.50 + 9.699 )

(65.801, 85.199)

<u><em>Final answer:-</em></u>

<em> The 99% confidence interval for the mean repair cost for the VCRs</em>

(65.801, 85.199)

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Which function corresponds with the table?
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