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FrozenT [24]
3 years ago
5

What is 20 x 10 to the power of 5

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

2000

Step-by-step explanation:

NikAS [45]3 years ago
8 0

Answer:

3.2e11 Or  32000000

Step-by-step explanation:

10 times 20

= 200

200^5

= 3.2e11

Or.....

10 times 20^5

= 32000000

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AYUDAAAAAAAAAAAA Un numero es 40% mas que el otro número, si la suma de 2 números es 84 busca los 2 números.
lions [1.4K]

Answer:

Si el número es x, entonces 1.4x + x = 84,

Entonces 2.4x = 84 yx = 84 / 2.4 = 840/24 = 35.

El otro número es 84-35 = 49

Step-by-step explanation:

Espero que te ayudo

Dejame saber : )

7 0
3 years ago
What is the result when the number 32 is increased by 25%?​
natulia [17]

Answer:

32, percentage increaced by 25% =40

Step-by-step explanation:

7 0
2 years ago
Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems
Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for (x_{1},y_{1})  and (x_{2},y_{2})

Use the distance formula to find the length =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length =\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\

length = \sqrt{80}

length = 8.94

Use the distance formula to find the width =\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width =\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\

width =\sqrt{(-10 )^{2} + (11 )^{2}}\\

width =\sqrt{100 + 121}\\

width = \sqrt{221}

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
Polygon ABCD has vertices A(1,3) , B(1,6) , C(4,6) , and D(5,2) .
Bond [772]

Answer:

  • check below for explanation.

explanation:

➢ Given coordinates:

  • A( 1, 3 )
  • B( 1, 6 )
  • C( 4, 6 )
  • D( 5, 2 )

➢ after a dilation with a scale factor of 1/2:

  • A( 1, 3 )  ÷  2    ☛   A'(0.5,1.5)  
  • B(1, 6 )   ÷  2    ☛   B'(0.5, 3)
  • C( 4, 6)  ÷  2    ☛  C'( 2, 3 )
  • D( 5, 2)  ÷  2    ☛  D'( 2.5, 1)

➢ Plot the after dilation coordinates on the graph:

  • check the image below:

5 0
2 years ago
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