for question 1
Area of Base B =45×25 = 1125 cm²
perimeter of base P = 2(45+25) = 140 cm
Height = 15 cm
Using the formula
Surface area = 2B + Ph
A = 2×1125 + 140×15= 4350 cm²
Voume = Bh = 1125×15= 16875 cm³
For question 2,
Area of base = 7× 5/2= 17.5 cm²
Perimeter of base = (7+7+7) = 21 cm
Surface area = 2B + Ph
Surface area of prism = 2×17.5+ 21×10 = 245cm²
Volume = Bh = 17.5×10 = 175 cm³
Switch y and x to find the inverse:
x = 3y - 8
Now just solve for y
y = x/3 + 8/3
Answer:
And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:
And the standard error is given by:
We want to construct a 68% confidence interval so then the significance level would be :
and 
. The confidence interval is given by:
Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:
And replacing we got:
And the best option would be:
D. (0.191 to 0.249)
Answer:
, The driver is 350 feet below sea level.
Step-by-step explanation:
The distance of the driver from the sea level is given by the following expression:
The driver is 350 feet below sea level.
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
