(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
30-5*4+2
30-20+2
10+2
12 is the answer
I believe the correct answer is 42.25%
Y > x
y = 2(3+x)
y = 3x-2
------------------------------
2(3+x) = 3x-2
2(3+x) - (3x-2) = 0
6 + 2x -3x + 2 = 0
8 -x = 0
x = 8
---------------------------
y = 2(3+x) = 2(3+8) = 22
y = 3x-2 = 3*8 -2 = 22
----------------------------------
x = 8 ; y = 22
Answer:
A. it is not a function because there are multiple y-values paired with a single x-value.
Step-by-step explanation:
