You can get 9 because in one foot there is 12 inches and there in 9 feet
Answer:
45 for 5 and 34 for 6.
Step-by-step explanation:
You are just subtracting by 11.
Answer:
Yes.
Step-by-step explanation:
This relation is a function because each input has one and only one output, i.e. 2 yields 1, 4 yields 2, 6 yields 3, 8 yields 4 and 10 has an output of 3. Therefore, it is a function.
The option are missing in the question. The options are :
A. P = 2, a = 1
B. 
C. 
D. P = 2, a = 3
Solution :
The given function is 
So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.
When the four option being substituted in the function, we get
A). It is a constant function since 
B). Here, the value of a is a fraction which is less than 1, so it is a decay function. 
C). It is a constant function since the value of a is 1.
D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

Therefore, option (D). represents an exponential function.
Answer:
A man who went by the name, "Pythagoras".