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vfiekz [6]
3 years ago
15

What is the value in cents 2 quarters, 3 dimes, and 4 nickels

Mathematics
2 answers:
Gemiola [76]3 years ago
7 0
112 Cents is the value
rewona [7]3 years ago
7 0

Answer:

100 cents or a dollar.

Step-by-step explanation:

.25+.25= .50

.50+ .30= .80

.80+.05+.05+.05+.05= 1.00

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Divide.<br>(10a^4-5a^3) / 5a
wolverine [178]
\boxed{\frac{10a^4-5a^3}{ 5a}=\frac{10a^4}{5a}-\frac{5a^3}{5a}=2a^3-a^2}
5 0
3 years ago
Please Help Me With All Four ​
svetlana [45]

Answer:

answer below

Step-by-step explanation:

a is: 0.8

b is : 2

c is: 5

d is: 12.5

6 0
3 years ago
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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
a line passes through the point (-9, 1) and had a slope of -2/3. Write an equation in point-slope form for this line
coldgirl [10]

Answer:

y-1=-2/3(x+9)

Step-by-step explanation:

y-1=-2/3(x-(-9))

y-1=-2/3(x+9)

7 0
3 years ago
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In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that th
deff fn [24]

Answer:

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 64

    The average price is  \= x  = \$ 112

    The population standard deviation is  \sigma  = \$ 16

     The level of significance is  \alpha  = 0.05

    The population mean is  \mu = \$ 108.5

The null hypothesis is  H_o :  \mu = 108.50

The alternative hypothesis is  H_a  :  \mu \ne  108.50

Generally the test statistics is mathematically represented as

       z = \frac{\= x - \mu }{ \frac{ \sigma}{\sqrt{n} } }

=>    z = \frac{112 - 108.50 }{ \frac{ 16}{\sqrt{64} } }  

=>    z = 1.75

From the z table  the area under the normal curve to the left corresponding to  1.75  is  

       P( Z >  1.75) = 0.040059

Generally  p-value is mathematically represented as

        p-value = 2 * P( Z >  1.75)

=>     p-value = 2 * 0.040059

=>     p-value = 0.08012

From the values obtained we see that  p-value  > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

 

3 0
3 years ago
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