Answer: you would use the last option
Answer:
second option: b = 0.8, h = 20
Step-by-step explanation:
areas are as follows:
14
16
13.5
14
Answer:
Step-by-step explanation:
4
Answer:
See attachment >_<
Step-by-step explanation:
Because the line includes the point 
, we'll begin our line at this coordinate.
The slope is 
, or, 
. Slope is formatted in the 
in the line over its 
. Or, 
. This means the line rises units and runs 
unit.
From our beginning point, , move up seven units and then to the right one unit.
If this line was negative (it would have a negative slope), we would run to the left. However, we have a positive slope, so we will run to the <em>right.</em>
By doing this, we land on the point 
. Draw a line through this point with our beginning coordinate . This is our graphed line. I've attached a photo as well :)
Good luck ^^
Answer:
it will take t= 12.64 seconds
Step-by-step explanation:
the voltage drop rate dV/dt will be
dV/dt=-k*V
then
∫dV/V=∫-kdt
ln(V/V₀)= -k*t
V=V₀*e^(-k*t)
in order for the voltage to drop 10 percent of its original value , then
(V₀-V)/V₀= 0.1 (10%)
[V₀- V₀*e^(-k*t) ] / V₀ = 0.1
1 - e^(-k*t) = 0.1
e^(-k*t) = 0.9
t = (- ln 0.9)/k = 120* (- ln 0.9) = 12.64 seconds
t= 12.64 seconds
