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riadik2000 [5.3K]
2 years ago
14

Find the slope of the line with these two points. (6 , -3) (4, - 5) m =

Mathematics
1 answer:
ss7ja [257]2 years ago
6 0

Answer:

m = 1

-5 - (-3)

--------       =    1

4 - 6

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"18 less than a number"
Dmitriy789 [7]

Answer:

18 is 1 and 8 put togother.

Step-by-step explanation:

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2 years ago
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1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the
ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

v_1 = 60\ mph

Sheyna drives back from the lake with average speed of 36 mph

v_2 = 36\ mph

It took 2 hours less time to get there than it did to get back.

Let t_1 be the time taken to drive to lake.

Let t_2 be the time taken to drive back from lake.

t_2-t_1 = 2 hrs ..... (1)

To find:

Total time taken = ?

t_1+t_2 = ?

Solution:

Let D be the distance to lake.

Formula for time is given as:

Time =\dfrac{Distance}{Speed }

t_1 = \dfrac{D}{60}\ hrs

t_2 = \dfrac{D}{36}\ hrs

Putting in equation (1):

\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles

So,

t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs

t_2 = \dfrac{180}{36}\ hrs = 5\ hrs

So, the answer is:

t_1+t_2 = \bold{8\ hrs}

8 0
3 years ago
What is the inverse of f(x) = sqft x+ 3
grin007 [14]

Answer:

f^{-1} (x)=x^{2} -3

Step-by-step explanation:

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f\left(x\right)=\sqrt{x+3}

We can find the inverse function by exchanging x and y, and then solve for y.

y=\sqrt{x+3}

Replace x with y.

x=\sqrt{y+3}

square both sides

x^2=y+3

y=x^2-3

Hence,

f^{-1} (x)=x^{2} -3

8 0
2 years ago
A water dispenser has the capacity of 25,000 milliliters. What is the capacity in liters
erica [24]

Since there are 1000 millilitres in 1 Liter. If we divide 25,000 by 1000 we get an answer of 25 Litres.

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3 years ago
Can someone assist me with this, I'm having problems with this
nirvana33 [79]
It’s true!! Hope this helped!!!!
8 0
2 years ago
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