I
tan(32)x21=13mm
j
7.32/cos(66)=17.9cm
k
tan(34)x26.8=18m
i
23.9/tan(49)=20.7km
:)Good luck in Math
OK so here it goes:
1a. 10³
1b. 10²
1c. 10(tiny 6)
1d. 10³
1e. 10(tiny6)
1f. 10(tiny 5)
2a. 400
2b. 640,000
2c. 5,400
2d. 5,301,000
2e. is it multipcation or addition
2f. 607,200
2g. 0.948
2h. 0.0094
3a) 0.02, 0.2, 2, 20, 200, 2000
3b) 3,400,000 ; 34,000; 340, 3.4, 0.034
3c) 85,700; 8,570; 857, 85.7, 8.57, 0.857
3d) 444, 4440, 44,400; 440,000; 4,400,000; 44,000,000
3e) 0.95, 9.5, 950, 95,000; 950,000; 9,500,000
Hope this helps.
Perpendicular has the reciprocal slope and u have to put the point given into point slope.
y-3=9/2(x-4)
(The slope of the original equation was -2/9)
Answer:
0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed
Step-by-step explanation:
The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:

In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

In this question:
Fleet of 17 means that 
4 are carrying nucleas weapons, which means that 
9 are destroyed, which means that 
What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?
This is:

In which

So



Then


0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed
3/4 times 16/9 is equal to 1 1/3.