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IRISSAK [1]
3 years ago
14

Consider the table of values for functions f and g below.

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

A. For every value of x, the rate of change of f exceeds the rate of change of g.

FALSE

Because the rate of change of f increases from 4 to 294, while the rate of change of g is constant (8).

B. As x increases, the rate of change of g exceeds the rate of change of f.

FALSE.

Because the rate of change of g is 8 (constant) and the rate of change of f starts at 4 and increases exceeding that of g.

C. At x = 2, the rate of change of f is equal to the rate of change of g.

FALSE

At x = 2 the rate of change of f is 12 and the rate of change of g is 8.

D. As x increases, the rate of change of f exceeds the rate of change of g.

TRUE

The rate of change of f at start is 4 and increases to 294, while the rate of change of g is 8 (constant), so as x increases, the rate of change of f exceeds the rate of change of g.

Explanation:

The rate of change of a function is calculated as:

  • rate of change = rise / run = change in y / change in x = Δy / Δx

For f(x) you get the following rates of change:

x     f(x)       Δy                       Δx                Δy/Δx

0      3         -                            -                     -

1       7       7-3 = 4                   1 - 0 = 1        4/1 = 4

2     19      19 - 7 = 12              2 - 1 = 1        12/1 = 12

3     55     55 - 19 = 36           3 - 2 = 1         36

4     163   163 - 55 = 108        4 - 3 = 2       108

5     457   457 - 163 = 294    5 - 4 = 1        294

From that, you see that the function f(x) is an increasing function with an increasing rate of change in the interval [0,5].

For g(x) you get f(x) you get the following rates of change:

x     g(x)       Δy                       Δx                Δy/Δx

0       3        

1       11        11 - 3 = 8             1 - 0 = 1             8

2     19       19 - 11 = 8             2 - 1 = 1             8

3     27      27 - 19 = 8            3 - 2 = 1            8

4     35     35 - 27 = 8            4 - 3 = 1            8

5     43   43 - 35 = 8              5 - 4 = 1            8

From that you can see that the function f(x) is increasing linear function, so its rates of change is constant.

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Which expression is equivalent to 1/4x+3-1/3x+(2)
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Answer:

5 - 1/12x.

Step-by-step explanation:

1/4x + 3 - 1/3x + (2)

= 1/4 x - 1/3 x + 3 + 2

=  3/12 x - 4/12 x + 5

= -1/12 x + 5.

4 0
2 years ago
If the sin of angle x is 4 over 5 and the triangle was dilated to be two times as big as the original, what would be the value o
beks73 [17]

Answer:

Sin of x does not change

Step-by-step explanation:

Whenever a triangle is dilated, the angle remains the same as well as the ratio for sides of triangle. For smshapes with dimensions, when shapes are dilated the dimensions has increment with common factor.

From trigonometry,

Sin(x)=opposite/hypotenose

Where x=4/5

Sin(4/5)= opposite/hypotenose

But we were given the scale factor of 2 which means the dilation is to two times big.

Then we have

Sin(x)=(2×opposite)/(2×hypotenose)

Then,if we divide by 2 the numerator and denominator we still have

Sin(x)=opposite/hypotenose

Which means the two in numerator and denominator is cancelled out.

Then we still have the same sin of x. as sin(4/5)

Hence,Sin of x does not change

4 0
3 years ago
What is the surface of the figure?<br><br> A. 136<br> B. 234<br> C. 236<br> D.246
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Is B. 224 in^2

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3 0
2 years ago
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rusak2 [61]
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7 0
3 years ago
Read 2 more answers
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
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