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PIT_PIT [208]
3 years ago
14

6 more than a number

Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

??

Step-by-step explanation:

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Find the value of x in the figure
quester [9]

Answer:

the correct ans is 37 .

(4x+2)° = 150°.... opposite angles of measure are

congruent.

4x+2 = 150

4x = 150-2

4x = 148

x = 148/4

x = 37.

4 0
3 years ago
Geometry question, I need help with this.
yaroslaw [1]

<u>1st transformation:</u> A vertical translation of the figure down by 8 units

<u>2nd transformation: </u>Shows a reflection on both axis and vertical translation up the plane by 8 units

<h3>Transformation of coordinates</h3>

Transformation is a way of changing the position of an object on an xy-plane.

For the translation

(x, y)-> (x, y-8)

It shows a vertical translation of the figure down by 8 units while the translation;

(x, y - 8) -> (-x, -y)

shows a reflection on both axis and vertical translation up the plane by 8 units

Learn more on transformation here: brainly.com/question/1462871

#SPJ1

7 0
2 years ago
V = u + at<br> u = 2 a = -7 t = 0.5
VashaNatasha [74]

v= u+ at

just put value bruuhh u can't even do this? alright

v=2+ (-7)(0.5)

v= -1.5

8 0
3 years ago
Question 1) When multiplying powers with the same base, keep the base and _______________ the exponents.
nika2105 [10]

The rules are

x^a\cdot x^b = x^{a+b}

\dfrac{x^a}{x^b} = x^{a-b}

Let me show you why with a couple of examples: suppose we want to multiply

4^3\cdot 4^2

Since powers are just repeated multiplications, we have

4^3\cdot 4^2 = \underbrace{4\cdot 4\cdot 4}_{4^3}\cdot\underbrace{4\cdot 4}_{4^2}=4^5 = 4^{3+2}

Similarly, we have

\dfrac{4^3}{4^2} = \dfrac{4\cdot 4 \cdot 4}{4\cdot 4} = 4 = 4^1 = 4^{3-2}

8 0
3 years ago
Subtract: ( - 2x4 - 4y + 4z² +6) - (-9x4 – 3y + 4z? +9) 0 - 7x² + y + 3 0 - 11x4 - 7 - 3​
Vinil7 [7]

Answer:  

36x-3y+4z^2+26-7x^2

Step-by-step explanation:

Okay well for starters, you can't subtract that because it's an expression, not an equation. And secondly, there was '?' which I'm going to assue=me was a typing error.

Now to actually simplify this mess of an expression, you just need to combine the like-terms! Once you do that you really can't do anything else, since you don't know the varibles.

5 0
3 years ago
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