Answer:
1 is C and 2 is B
Step-by-step explanation:
Answer:
4/10 : 1/25
4/10 / 1/25 = 4/10 x 25/1 = 100/10 = 10.
10 can also be written as 10:1, so A is correct.
Hope this helps!
The limit of the expression as x approaches -3 is -24
<h3>How to determine the limit of the expression?</h3>
The expression is given as:

As x approaches -3.
The limit expression becomes

Substitute -3 for x in the expression

Evaluate the expression

Hence, the limit of the expression as x approaches -3 is -24
Read more about limit expressions at:
brainly.com/question/16176002
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Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:


Z = 1.16
Z = 1.16 has a p-value of 0.877.
0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
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