Answer:
Two polygons are similar with factor k.
=> The ratio between the area of two polygons: r = k^2
=> Here, the area of polygon B is larger than polygon A: 5^2 = 25 times
Hope this helps!
:)
I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.
Now write the tangent ratios:

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent

Plug in what we know:



(7/3 *3sqrt27-2)*1/5 +sqrt(81)
answer = 10
Step-by-step explanation:
On each side of this quadrilateral, you have supplementary angles, in other wourds, angles that sum up to <em>one hundred eighty degrees</em>:
![\displaystyle 180° = [3y + 14]° + [10y - 29]° \\ 180° = [-15 + 13y]° \\ \frac{195}{13} = \frac{13y}{13} \\ \\ 15 = y; 59° = [3(15) + 14]° \\ \\ \\ \\ 180° = [5x - 2]° + [x + 14]° \\ 180° = [12 + 6x]° \\ \frac{168}{6} = \frac{6x}{6} \\ \\ 28 = x; 138° = [5(28) - 2]°](https://tex.z-dn.net/?f=%5Cdisplaystyle%20180%C2%B0%20%3D%20%5B3y%20%2B%2014%5D%C2%B0%20%2B%20%5B10y%20-%2029%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B-15%20%2B%2013y%5D%C2%B0%20%5C%5C%20%5Cfrac%7B195%7D%7B13%7D%20%3D%20%5Cfrac%7B13y%7D%7B13%7D%20%5C%5C%20%5C%5C%2015%20%3D%20y%3B%2059%C2%B0%20%3D%20%5B3%2815%29%20%2B%2014%5D%C2%B0%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5C%20180%C2%B0%20%3D%20%5B5x%20-%202%5D%C2%B0%20%2B%20%5Bx%20%2B%2014%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B12%20%2B%206x%5D%C2%B0%20%5C%5C%20%5Cfrac%7B168%7D%7B6%7D%20%3D%20%5Cfrac%7B6x%7D%7B6%7D%20%5C%5C%20%5C%5C%2028%20%3D%20x%3B%20138%C2%B0%20%3D%20%5B5%2828%29%20-%202%5D%C2%B0)
I am joyous to assist you at any time.