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2 years ago

Please need help on this not too sure on this

Mathematics

1 answer:

kifflom [539]2 years ago

8 0

option 3

they are corresponding angles and are congruent

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What is 789 times 26372

Rus_ich [418]

Answer:

20807508

Step-by-step explanation:20807508

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3 years ago

A cylinder with radius 3 feet and height 5 feet is shown.

Leviafan [203]

Answer:

The volume of the cylinder is <u>141.23 cubic feet </u>

Step by step explanation :

<u>Given</u>-

Radius of cylinder = 3 feet
Height of cylinder = 5 feet

Now, we know that

<h3> $\boxed {\mathfrak \red{ volume \: of \: cylinder = \pi {r}^{2} h}}$ </h3>

where, r is the radius of the cylinder & h is the height of the cylinder.

Now,

Volume of the cylinder = $\frac{22}{7} \times {3}^{2} \times 5$

$= \frac{22}{7} \times 3 \times 3 \times 5$

$= 141.428571$ ( approximately )

$= \boxed{ 141.43 \: \mathfrak { {ft}^{3}} }$

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1 year ago

Quadrilateral RSTU is a parallelogram. What must be the value of x?

Luba_88 [7]

I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5

7 0

2 years ago

Read 2 more answers

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

Evaluate the expression a3 -b/c for a = 3, b = 2 and c = 4. write in simplest form

Scilla [17]

Hello There!

Write out your equation:
$(a^3 - b)/c$
Substitute the values in:
$(3^3 - 2)/4$
Simplify:
$(27 - 2)/4$
$25/4$
Solve:
It is 6.25.

Therefore, your answer is 6 1/4.

Hope This Helps You!
Good Luck :)

- Hannah ❤

6 0

3 years ago