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alina1380 [7]
2 years ago
9

Mr. Parker bought a coat when it was on sale. He paid 70% of the original price. He paid $42 for the coat. What was the original

cost of the coat?
Mathematics
2 answers:
fenix001 [56]2 years ago
6 0

Answer:

70percent =42

100percent ×42 ÷70

100/7×42

10/7×42=60

therefore the original cost was $60

Alchen [17]2 years ago
3 0
The answer is $60 because we know %70 of the original price is $42.
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The table shows a linear relationship between x and y
irga5000 [103]

We have been given a table that shows a linear relationship between x and y. We are asked to find the rate of change change of y with respect to x.

To solve our given problem, we will find the slope of the line passing through the given points.

m=\frac{y_2-y_1}{x_2-x_1}

Let us find slope of line using points (-20,96) and (-2,15).

m=\frac{15-96}{-2-(-20)}

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m=\frac{-81}{18}

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Therefore, the rate of change of y with respect to x is -4.5.

3 0
3 years ago
0= -115<br> sin=<br> cos =<br> tan
Alina [70]

Answer:

Step-by-step explanation:

Tito wants to buy some peanut butter to donate as much as possible.

There some brands are given with their price.

we will calculate the price of per ounce peanut butter of each brand.

A. Nutty : 12 ounces for $2.19

cost per ounce =

                        = $0.1825 ≈ $0.18 per ounce

B. Grandma's : 18 ounces for $2.79

cost per ounce =

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C. Bee's : 0.28 ounces for $4.69

cost per ounce =

                        = $16.75 per ounce

D. Save-A-Lot : 40 ounces for $6.60

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8 0
3 years ago
ILL GIVE YOU BRAINLIST !! * have to get it right !!! * Find the slope of the line.
sveticcg [70]

Answer:

slope is 2

Step-by-step explanation:

Find two points that can be used.

(0,4) (2,8)

Use the slope formula and plug in the numbers

\frac{y_{1}-y_{2}  }{x_{1}-x_{2}  }

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\frac{4}{2}

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5 0
4 years ago
Question 1
Alexxx [7]

Answer:

Water needed for pool = 486 cubic feet

Plastic liner required for the pool = 298.3 feet

Step-by-step explanation:

Top view of the pool is a composite figure, having one rectangle and a trapezoid.

1). Water needed for the pool = volume of the pool

Volume of the pool = Area of the base × Depth

                               = (Area of the rectangle + Area of the trapezoid)× depth  

Area of the trapezoid = \frac{1}{2}(b_{1}+b_{2})\times h

                                    = \frac{1}{2}(11+9)\times (12-1.5)

                                    = 105 ft²

Area of the rectangle = Length × width

                                    = 11 × 1.5

                                    = 16.5 ft²

Now, volume of the pool = (105 + 16.5) × 4

                                          = 121.5 × 4

                                          = 486 cubic feet

b). Liner required = surface area of the pool excluding top

                             = Surface area of the walls + Area of the pool base

                             = (Perimeter of the pool) × depth + area of the base

                             = (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5

                             = 176.8 + 121.5

                             = 298.3 square feet

Therefore, amount of water required = 486 cubic feet

liner needed = 298.3 square feet                                  

8 0
3 years ago
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