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3 years ago

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The ages of 3 brothers are represented by consecutive integers. If the oldest brother's age is decreased by twice the younger br

other's age, the result is -19. How old is the youngest brother?

1 answer:

ANEK [815]3 years ago

3 0

Answer:

The age of youngest brother is <u>21</u>.

Step-by-step explanation:

Given:

The ages of 3 brothers are represented by consecutive integers.

If the oldest brother's age is decreased by twice the younger brother's age, the result is -19.

Now, to find the age of youngest brother.

Let the age of youngest brother be $a-1.$

Let the age of middle one be $a$ .

And the age of oldest brother age be $a+1.$

According to question:

$(a+1)-2(a-1)=-19$

⇒ $a+1-2a+2=-19$

⇒ $-a+3=-19$

Adding $a$ on both sides we get:

⇒ $2=-19+a$

Adding 19 on both sides we get:

⇒ $22=a$

Now, getting the age of youngest brother by putting the value of $a$ :

$a-1$

⇒ $=22-1=21.$

Therefore, the age of youngest brother is 21.

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