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Verdich [7]
3 years ago
8

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

than or equal to 0
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

\frac{\sqrt[3]{16y^4}}{x^2}

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices \sqrt[n]{a}  = a^{\frac{1}{n}}

So,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } gives

\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}

Also from laws of indices

(ab)^n = a^nb^n

So, the above expression can be further simplified to

\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}

Multiply the exponents gives

\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

Substitute 2^5 for 32

\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}

From laws of indices

\frac{a^m}{a^n} = a^{m-n}

This law can be applied to the expression above;

\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})} becomes

2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}

Solve exponents

2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}

From laws of indices,

a^{-n} = \frac{1}{a^n}; So,

2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}} gives

\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}

The expression at the numerator can be combined to give

\frac{(2y)^{\frac{4}{3}}}{x^2}

Lastly, From laws of indices,

a^{\frac{m}{n} = \sqrt[n]{a^m}; So,

\frac{(2y)^{\frac{4}{3}}}{x^2} becomes

\frac{\sqrt[3]{(2y)}^{4}}{x^2}

\frac{\sqrt[3]{16y^4}}{x^2}

Hence,

\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} } is equivalent to \frac{\sqrt[3]{16y^4}}{x^2}

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72.3 + (-39.1)
joja [24]

Answer:

72.3 - 39.1 = 4tens - 7ones + 2tenth

Step-by-step explanation:

Give the expression 72.3 + (-39.1)

opening the parenthesis:

= 72.3 + (-39.1)

= 72.3 - 39.1

Breaking the decimal values into place values

72.3 = 7tens + 2units + 3tenth

72.3 = 7(10)+2(1)+3(1/10)

72.3 =70+2+0.3

Similarly for 39.1

39.1 = 3tens + 9units + 1tenth

39.1 = 3(10)+9(1)+1(1/10)

39.1 =30+9+0.1

72.3 - 39.1 = 70+2+0.3 - (30+9+0.1)

72.3 - 39.1 = 70+2+0.3 - 30-9-0.1

72.3 - 39.1  = 70-30+2-9+0.3-0.1

72.3 - 39.1 = 40 - 7 +0.2

72.3 - 39.1 = 4tens - 7ones + 2tenth

3 0
2 years ago
Neil is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?
SashulF [63]
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(a) Find the perimeter of the shape below. (Take π =<br>22/7)<br>3cm<br>3cm<br>12cm<br>20cm​
MariettaO [177]
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it’s correct
3 0
3 years ago
Find out the product of 2,12 and 3
drek231 [11]
You mean 2x3x12? if yes, it is 72.
8 0
3 years ago
Read 2 more answers
A moving box has a square base with an area of 324 in². It's height is 24 inches. What is the volume of the moving box?
Roman55 [17]

The volume of the moving box will be 7776 cubic inches,.

<h3>What is the volume of the rectangular prism?</h3>

Let the prism with a length of L, a width of W, and a height of H. Then the volume of the prism is given as

V = L × W × H

V = Base area x height

A moving box has a square base with an area of 324 in².

Its height is 24 inches.

Then the volume of the moving box will be

V = Base area x height

V = 324 x 24

V = 7776 cubic inches

More about the volume of the prism link is given below.

brainly.com/question/16246207

#SPJ1

3 0
1 year ago
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