Answer:
Step-by-step explanation:
Given that;
Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16
Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26
Compressed soil intermediate soil
Mean 2.907 3.286
SD 0.1414 0.2377
Here we have,
The pooled Standard deviation
So standard error for difference in population mean is
by inputting the values we get 0.0623
Degree of freedom for t is
df = 19 + 20 - 2 = 37,
so t-critical value is 2.715.
So required confidence interval for
will be
So required confidence interval is (0.2103 , 0.5483).
Answer:
A.
Step-by-step explanation:
5>4
6>2
5 is greater than 4, 6 is greater than 2
Complete question:
Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?
Answer:
Here,
Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)
We are also told only 10 participants are available.
All 10 participants are being exposed to all five levels of the color variable in the same order.
Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.
Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.
But using counterbalancing technique, Dr. Lyte can avoid such an error.
We can change the sign of the second term, so that the two parenthesis are the same:
Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have
The parenthesis (a-1) is also in common, so we can factor it as well:
Finally, both terms in the parenthesis contain 
, because it's the power of b with the lowest exponent:
So, the factorization is
You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.
