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Kisachek [45]
3 years ago
9

Pls help me factorize.Thanks!

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

We can change the sign of the second term, so that the two parenthesis are the same:

6(a-1)b^3+3(1-a)b^2 = 6(a-1)b^3-3(a-1)b^2

Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have

6(a-1)b^3-3(a-1)b^2 = 3(2(a-1)b^3-(a-1)b^2)

The parenthesis (a-1) is also in common, so we can factor it as well:

3(2(a-1)b^3-(a-1)b^2) = 3(a-1)(2b^3-b^2)

Finally, both terms in the parenthesis contain b^2, because it's the power of b with the lowest exponent:

3(a-1)(2b^3-b^2) =3(a-1)b^2(2b-1)

So, the factorization is

3b^2(a-1)(2b-1)

You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.

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