All categories

1 year ago

I need help with this pls

Mathematics

1 answer:

Alexxx [7]1 year ago

5 0

Hello!

What is an x-intercept:

⇒ value of x when the value of y equals '0'

$8x + 5y=25\\8x+5(0)=25\\8x=25\\\\x=\dfrac{25}{8}$

x-intercept is 25/8

What is a y-intercept:

⇒ value of y when the value of x equals '0'

$8x+5y=25\\8(0)+5y=25\\5y=25\\y=5$

y-intercept is 5

Hope that helps!

You might be interested in

What is a number that when you divide it by 4 and subtract 3 from the quotient, you get 13?

inysia [295]

$64$

$64 \div 4 = 16$

$16 - 3 = 13$

8 0

2 years ago

Read 2 more answers

What is the ratio of 140:160

levacccp [35]

Answer:

it reduces to 7:8

Step-by-step explanation:

just put it like a fraction like 140/160. it simplifies to 7/8

4 0

3 years ago

What is the nth term of the sequence -2 -8 -18 -32 -50

andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
$T_{n} = an^{2} +bn +c$

To find the value of a we just divide second difference ( -4 ) by 2:

$a = \frac{-4}{2}= -2$

Now we have:

$T_{n}= -2n^{2} +bn+c$

Substitute $n_{1}$ and $n_{2}$ into the equation above:

$T_{1} = -2(1)^{2} +b(1) +c$

$T_{2} = -2(2)^{2} +b(2)+c$

Since $T_{1}$ = -2 and $T_{2}$ = -8 , after simplification we have:

$b +c =0$
$2b+c=0$

The solution of this system is:

b=0, c =0

The general term is :

$T_{n} = -2n^{2}$

6 0

2 years ago

In ΔUVW, the measure of ∠W=90°, VW = 32 feet, and WU = 78 feet. Find the measure of ∠V to the nearest degree.

DanielleElmas [232]

Answer: $67.68^{\circ}$

Step-by-step explanation:

Given

$\angle W=90^{\circ}$

$VW=32\ ft$

$WU=78\ ft$

from the figure, we can write

$\Rightarrow \tan v=\dfrac{UW}{VW}\\\\\Rightarrow \tan v=\dfrac{78}{32}\\\\\Rightarrow \tan v=2.437\\\Rightarrow v=\tan^-1(2.437)\\\Rightarrow v=67.68^{\circ}$

7 0

3 years ago

PLEASE HELPPPPP!!!!!!!!! (show work if you can)

Kryger [21]

Answer:

$180x^4y^3z^2$

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

$LCM(12,18,30)=180$

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term ( $x$ , $y$ , and $z$ ). The largest term of $x$ is $x^4$ in the first polynomial, so we'll take exactly that for our $x$ term in the LCM, absolutely nothing more. Similarly, the largest term of $y$ in any of the three polynomials is $y^3$ (also in the first polynomial) and the largest $z$ term in any of the three polynomials is $z^2$ in the second polynomial. Thus, the LCM of all our polynomials is:

$180\cdot x^4\cdot y^3\cdot z^2=\boxed{180x^4y^3z^2}$

3 0

3 years ago

Read 2 more answers