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1 year ago

I need help with this pls

Mathematics

1 answer:

Alexxx [7]1 year ago

5 0

Hello!

What is an x-intercept:

⇒ value of x when the value of y equals '0'

$8x + 5y=25\\8x+5(0)=25\\8x=25\\\\x=\dfrac{25}{8}$

x-intercept is 25/8

What is a y-intercept:

⇒ value of y when the value of x equals '0'

$8x+5y=25\\8(0)+5y=25\\5y=25\\y=5$

y-intercept is 5

Hope that helps!

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Juan earns 20% commission as a salesperson. He sold a trampoline that cost $86.40 How

andreev551 [17]

Answer:

$17.28

Step-by-step explanation:

20% of $86.40

= $\frac{20}{100}$ × $86.40

= 0.2 × $86.40

= $17.28 ← commission

3 0

1 year ago

A frozen pizza is on sale at a 25% discount. Find the sales price of the pizzas if it normally sells for $4.85.

bonufazy [111]

The best thing to do here is to divide $4.85 by 10, and then multiply it by 2.5. $4.85/10= $0.48. $0.48x2.5= $1.20 Therefore,the discount is $1.20, you've then got to subtract this from $4.85. $4.85-$1.20= $3.65 $3.65 is the sale price of the pizza. Hope this helps :)

4 0

3 years ago

Can you please help me

SashulF [63]

9514 1404 393

Answer:

(x, y, z) = (90, 75, 105)

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary, and opposite angles are congruent.

(x -15) +(x +15) = 180

2x = 180

x = 90

Angles y and (x-15) are opposites, so ...

y = x -15 = 90 -15 = 75

Similarly, for z ...

z = x +15 = 90 +15 = 105

The values of x, y, and z are 90, 75, and 105, respectively.

6 0

2 years ago

Select the correct answer.

DerKrebs [107]

I’m pretty sure the answer is c

8 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

7 0

3 years ago