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kap26 [50]
3 years ago
10

294 to the nearest 1000

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0
The answer is 0 since when you round it to thousandth you make it 0 but if more than 500 shove it into place.


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Cho f(t)=(t-4)u(t-2)phep bien doi laplace la<br> F(s)=e^-2s/s^2-2e^-2s/s62
FinnZ [79.3K]

Step-by-step explanation:

cho f(t)=(t-4)u(t-2)phep bien doi laplace la

F(s)=e^-2s/s^2-2e^-2s/s62

4 0
3 years ago
4x + 1 + x = -4<br> Can anybody help me solve this ?
ValentinkaMS [17]

Answer:

Simplify the equation

Step-by-step explanation:

4x + 1 + x + -4

= 4x + x + 1 - 4

= 5x + -3

= 5x - 3

Hope this helps

7 0
3 years ago
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Eva8 [605]

Answer:

The diameter is 5 cm and the circumference is diameter x pi

Step-by-step explanation:

3 0
3 years ago
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valentinak56 [21]

Answer:

The answer is C. 8 mm

Step-by-step explanation:

For me, i was able to divide the 80 by 12 and get 6.667 thus i was able to round up and conclude the answer in the answer choices

7 0
3 years ago
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Given a group of 17 people in a party, we consider the number of times a person shakes hand with someone else. Show that there i
aev [14]

Answer:

Step-by-step explanation:

Given that there is a group of 17 people in a party.  There takes place a number of hand shakes between them.

To show that there is always two people who shake hands with the same total number of people.

If possible let each person did a different number of handshake.

We know that since there are 17 people, there cannot be more than 16 hand shakes for any one in the group.

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Consider the last person having 16 hand shakes. He has shaken hand with each other person in the group thus making it clear that no one could have done 0 hand shakes.   Since we get a contradiction, our assumption was wrong. That is, there is always two people who shake hands with the same total number of people.

8 0
3 years ago
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