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madam [21]
3 years ago
11

A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 5 tables is $52. The total cost to re

nt 9 chairs and 7 tables is $86. What is the cost to rent each chair and each table?
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

The cost for 1 chair is $2.75 and the cost for 1 table is $8.75

Step-by-step explanation:

Use the elimination method of linear equations to find your answer.

Our equations for this problem are:

3c+5t=52 and 9c+7t=86

1. Multiply the entire first equation by -3.

-3(3c+5t=52)

2. Simplify the equation from above:

-9c-15t=-156

3. Stack the two equations on top of each other and add/subtract:

-9c-15t=-156

9c+7t=86

4. You should be left with -8t=-70. Simplify this to find the value of t:

t=8.75

5. Plug the value of t into any of the original equations and solve for c.

3c+5(8.75)=52

6. Simplify the equation above:

3c+43.75=52

7. Subtract 43.75 from both sides of the equation:

3c=8.25

8. Divide both sides by 3 to get your c value:

c=2.75

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Answer:

15 games.

Step-by-step explanation:

Here is the complete question: The admission fee to a video game arcade is $1.25 per person, and it costs $0.50 for each game played. Latoya and donnetta have total $10.00 to spend. What is the greatest number of games they will be able to play?

Given: Admission fees= $1.25 per person.

           Cost of each game played= $0.50.

           Total Money, Latoya and Donnetta have is $10.

First lets find total admission fees both will pay.

∴ Total addmission fees= Fees\ per\ person \times number\ of\ person

Total addmission fees= \$1.25\times 2= \$ 2.50

Now, money remaining after paying admission fees.

Money remaining = Total\ money - Admission\ fees

∴ Money remaining = \$10-\$2.5= \$ 7.5

∴ Money remained to play video games is $7.5.

Next, finding the maximum number of games, both will be able to play.

As we know, each game will cost $0.50.

Total number of games played= \frac{Money\ remaining}{Cost\ of\ each\ game}

⇒ Total number of games played=\frac{\$ 7.5}{\$ 0.5} = 15\ games

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=135.53°

Step-by-step explanation:

The bearing that the captain should turn is the angle difference between the two islands from the position of the ship.

Let C be the position of the ship, then

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88000 Cos C=88400-25600

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Divide both sides by 88000.

Cos C=62800/88000

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C=44.47°

He should turn (180°-44.47°)=135.53°

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