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miss Akunina [59]

3 years ago

5

A garden table and a bench cost $450 combines. The cost of the garden table is two times the cost of the bench. What is the cost

of the bench?

1 answer:

nordsb [41]3 years ago

5 0

Answer:

150

Step-by-step explanation:

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Z^2 + 2z + 5 , when z = 2 , z^2 is "z squared

OverLord2011 [107]

Answer:

=13

Step-by-step explanation:

=2^2+2×2+5

=4+4+5

=8+5

=13

3 0

3 years ago

An artist agrees to paint a landscape painting at 0.30 per square inch. if the painting is 13 inches by 17 inches, how much shou

Yuri [45]

We know that
[area of the painting]=13 in* 17 in-----> 221 in²

if a<span>n artist painting at
$0.30 per --------------> 1 in</span>²
x$--------------> 221 in²
X=221*0.30------> x=$66.30

the answer is
$66.30

8 0

3 years ago

4.5 meters equals how many centimeters

icang [17]

450 centimeters because there are 100 centimeters in a meter.

4 0

4 years ago

Read 2 more answers

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

How many odd numbers are there between twenty and forty?

inna [77]

Answer:

Total 10

Step-by-step explanation:

21. 23, 25, 27, 29, 31 , 33, 35, 37, 39.

hope this helps you

5 0

2 years ago