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3 years ago

14

Sadie used 333.3 gallons of water over the course of 3 days. How much water did Sadie use, on average, each day?

1 answer:

Rashid [163]3 years ago

3 0

Answer: 111.1

Step-by-step explanation: 333.3/3 = 111.1

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An a adult ticket to the zoo costs $20 and a child’s ticket costs $10.How much will it cost for Mr. and Mrs.Brown and their 4 ch

liubo4ka [24]

Answer:

Step-by-step explanation:

you add 20 for mr brown 20 for mrs brown 10 for kid one 10 for kid 2 ten for kid 3 and 10 for kid for giving you a grand total of 80 dollars

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2 years ago

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Adding proper fractions .. 10/12+6/12=need help

mixas84 [53]

Adding fractions is easy when you get the rules...
10/12 + 6/12...
add the numerator which is the top, and keep the denominator which is the bottom.
10/12 +6/12 = 16/12
change that into a mixed number
16/12 = 1 4/12 which is simplified to 1 1/3
hope this helps

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3 years ago

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3.5,-2,0,-7/3,-6 in order from greatest to least

icang [17]

Answer:

in order from greatest to least:

3.5 0 -2 -7/3 -6

Step-by-step explanation:

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3 years ago

A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.

GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: $A(x) = x^2$ but we aim to find $\frac{dA}{dt}$ . But we can use the chain rule to pull out that dA/dt. Doing so gives us:

$\frac{dA}{dt} = \frac{dA}{dx} \times \frac{dx}{dt}.$

Now, $\frac{dA}{dx} = 2x$ (by the power rule and $\frac{dx}{dt} = 3.$

But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.

So, finally, we see that:

$\frac{dA}{dt} = 2(7) \times 3 = 14 \times 3 = 42.$

7 0

3 years ago

The gross domestic product (GDP) of a certain country, which measures the overall size of the economy in billions of dollars, ca

DiKsa [7]

Answer:

The estimated GDP in 2007 is 12782 billion dollars.

The estimated GDP in 2011 is 15010 billion dollars.

The estimated GDP in 2012 is 15567 billion dollars.

Step-by-step explanation:

Consider the provided function.

$g(y) = 557y +8883$

Where y = 10 corresponds to the year 2010.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2007.

If y = 10 corresponds to the year 2010 then y = 7 corresponds to the year 2007.

Substitute the value of y = 7 in the provided function.

$g(y) = 557(7) +8883$

$g(y) = 3899+8883$

$g(y) = 12782$

Hence, the estimated GDP in 2007 is 12782 billion dollars.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2011.

If y = 10 corresponds to the year 2010 then y = 11 corresponds to the year 2011.

Substitute the value of y = 11 in the provided function.

$g(y) = 557(11) +8883$

$g(y) = 6127+8883$

$g(y) = 15010$

Hence, the estimated GDP in 2011 is 15010 billion dollars.

Part (C) Estimate the GDP (to the nearest billion dollars) in 2012.

If y = 10 corresponds to the year 2010 then y = 12 corresponds to the year 2012.

Substitute the value of y = 12 in the provided function.

$g(y) = 557(12) +8883$

$g(y) = 6684+8883$

$g(y) = 15567$

Hence, the estimated GDP in 2012 is 15567 billion dollars.

4 0

3 years ago