We would first input the numbers in the equation.
6(6/3)-2(3)
Then, we will solve the problem inside the parenthesis. Remember PEMDAS.
6(2)-2(3)
Then we multiply!
12-6
The final answer is 6, hope it helped!
Hello,
2ay²+5ay-3a=a(2y²+5y-3)
=a(2y²+6y-y-3)=a(2y(y+3)-(y+3))
=a(y+3)(2y-1)
y=3/3x+-2
Step-by-step explanation:
it goes up 3 and over 3 so its 3/3 and it starts at -2
Answer:
A, B, and C are all true.
Step-by-step explanation:
A. 6 is neither a perfect square nor a perfect cube. True
B. 16 is a perfect square. True 
C. 27 is a perfect cube. True 
OD. 1,331 is both a perfect square and a perfect cube. False
E. 9 is a perfect cube. False