the AnSwEr is
12 because 8x - 1=3x+4 the variable x represents the same value and x= 0
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
The first thing is the slope
y = 1/2 x + b is the new line. Now we must solve for b
2 = 1/2 (-2) + b
2 = -1 + b
3 = b
The new line is
y = 1/2 x +3
0.6% of 1300
Convert <span>0.6%</span><span> to a decimal.
</span><span>0.006⋅1300
</span>Multiply 0.006<span> by </span>1300<span> to get </span><span>7.8.
</span>7.8
Z° + 43° = 180°-------(linear angles)
z° = 180 - 43°
z = 137°
Hope this helps.