Answer:
a) 0.62%
b) 518 g
Step-by-step explanation:
a)
Here we want the area under the Normal curve of mean
= 500 g and standard deviation s = 10 g to the left of 475 (the probability that the machine produces a box with less than 475 g of cereal).
With the help of a spreadsheet we found that value is 0.0062 or 0.62% (another way of seeing it is that 62 boxes out of 10,000 will have 475 g or less)
<h3>See picture</h3>
b)
Here we want to find a value of
such that the area of the Normal curve of mean
and standard deviation 10 to the left of 500 is 4% or 0.04
If we make the change
![\bf z=\frac{500-\mu}{s}](https://tex.z-dn.net/?f=%5Cbf%20z%3D%5Cfrac%7B500-%5Cmu%7D%7Bs%7D)
then this is equivalent to finding a value of z for which the area under the Normal curve N(0,1) (mean = 0 s = 1) to the left of z is 4% = 0.04
Either by using a table or spreadsheet, we find that value is z = -1.751
So,
![\bf z=\frac{500-\mu}{s}\rightarrow -1.751=\frac{500-\mu}{10}\rightarrow \mu=500+10*1.751=517.51](https://tex.z-dn.net/?f=%5Cbf%20z%3D%5Cfrac%7B500-%5Cmu%7D%7Bs%7D%5Crightarrow%20-1.751%3D%5Cfrac%7B500-%5Cmu%7D%7B10%7D%5Crightarrow%20%5Cmu%3D500%2B10%2A1.751%3D517.51)
and the manufacturer must set its filling machine to the target weight of 518 g.
Answer:
A picture
Step-by-step explanation:
Answer:
2, 6
Step-by-step explanation:
i dont know
Answer:
3 6/8
Step-by-step explanation:
5 = 5
10/8 = 1 2/8
5 - 1 = 4
4 - 2/8 = 3 6/8
Solve:-
28 ÷ 0.7 = 40
28m ÷ 0.7m = 40
0.7 goes 40 times in 28m.