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kumpel [21]
3 years ago
12

In ideal conditions, 200 colony-forming units (cfu) of E. coli can grow to 400 cfu in 20 minutes, to 800 cfu in 40 minutes, and

to 1600 cfu in an hour.
Part A: Jenny says that the E. coli growth can be modeled with an exponential function. Do you agree? Justify your answer.

Part B: Write the equation that models the function.Immersive Reader
Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

(a)Yes, it is an exponential function.

(b)P(t)=200\cdot 2^{t/20}

Step-by-step explanation:

(a)A population grows exponentially if it increases by a common ratio(called the growth ratio). We can see from the given information that the population of E.coli doubles every 20 minutes, therefore it is an exponential growth with a growth ratio of 2.

(b)The population, P(t) at any time t of an initial population, P_o  with a growth ratio of r over a period k can be modeled using the function:

P(t)=P_o\cdot r^{t/k}

In this Case:

P_o=200

Growth rate,r=2

Growth Period,k=20 minutes

Therefore, the equation that models the function is:

P(t)=200\cdot 2^{t/20} , t is in minutes

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