The sum of two and the quotient of a number x and fine.
sum= +
two= 2
quotient= divide
five= 5
2+ x/5 <- should look something like this
I hope this helps!
~kaikers
First of all, we can observe that
So the expression becomes
This means that the expression is defined for every 
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask
Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
<em>Answer</em>
= 11
<em>Explanation</em>
f(x) = x² + 3x- 7
To get the value of f(x) when x = 3, we substitute x with 3 in the function f(x).
f(x) = x² + 3x- 7
= 3² + (3×3) -7
= 9 + 9 - 7
= 11
The solution is false!
3.1 would become a fraction that will be calculated back into a decimal by the 4th power making it 92.3521=3,600.. so the equality is false because the left hand and the right hand side are different.
