Ask question

Ask question

All categories

3 years ago

13

what are the solution(s) to the quadratic equation 9x^2 = 4? a. x = 4/9 and x = -4/9 b. x = 2/3and x = -2/3 c. x = 3/2 and x = -

3/2 d. no real solution

1 answer:

wolverine [178]3 years ago

3 0

$9x^2 = 4 \\ x^2 = \frac{4}{9} \\ x= \pm \sqrt{ \frac{4}{9} } \\ x= \pm \frac{2}{3}$
solution is <span>x = 2/3 and x = -2/3</span>

You might be interested in

Help plz??????????????????????????????

Juliette [100K]

I would go with -15 that’s what I came up with

8 0

4 years ago

Calculus help needed!

mezya [45]

$f(x)=\ln x\\\\g(x)=\ln11x=\ln11+\ln x\ \ (\ln11=const.)\\\\h(x)=\ln x^2=2\ln x\\\\p(x)=\ln3x^2=\ln 3+\ln x^2=\ln3+2\ln x\ \ (\ln3=const.)$

Used:

$\ln a+\ln b=\ln(ab)\\\\\ln a^n=n\log a$

Functions have the same derivatives if they differ a constant.

h(x) = f(x); g(x) = f(x) + const.

h'(x) = f'(x)

g'(x) = (f(x) + const.)' = f'(x) + (const.)' = f'(x) + 0 = f'(x)

h'(x) = g'(x)

Therefore yuor answer is A. f'(x)=g'(x)

$f'(x)=(\ln x)'=\dfrac{1}{x}\\\\g'(x)=(\ln11x)=\dfrac{1}{11x}\cdot11=\dfrac{1}{x}$

Used:

$(\ln x)'=\dfrac{1}{x}\\\\f'(g(x))=f'(g(x))\cdot g'(x)$

6 0

3 years ago

18 decreased by 3 times d

babymother [125]

I’m unsure of what u r asking, I think 6 is ur answer

5 0

4 years ago

On Saturday, a souvenir shop had 125 customers. Sixty-four percent of the customers paid with a credit card. The other customers

wel

Answer:

45 customers

Step-by-step explanation:

Given

Total number of customers = 125

percent that paid with credit card = 64%

Customers that paid with credit card = 64% * 125

Customers that paid with credit card = 0.64 * 125 = 80

Number of customers that paid with cash = 125 - 80

Number of customers that paid with cash = 45 customers

7 0

3 years ago

If correct I’ll give brainlest pls help

VladimirAG [237]

Answer:

C

Step-by-step explanation:

I did that test before we trusty meee

7 0

3 years ago