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Angelina_Jolie [31]
3 years ago
7

How much is a 1 paint set if I spent 16.45 on 5 of the ?

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

$3.29

Step-by-step explanation:

16.45 divided by 5 is 3.29

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Find the area of the rhombus if AE = 20 m and DE = 32 m
Fudgin [204]
We have to calculate the area of the rhombus if AE = 20 m and DE = 32 m.The diagonals DB = 2 * DE and AC = 2 * AE.
DB = 2 * 32 = 64 mAC = 2 * 20 = 40 mArea = d1 * d2 / 2 = DB * AC / 2 = 64 * 40 / 2 = 1,280 m²Answer: The area of the rhombus is B ) 1,280 m².
4 0
3 years ago
Which expression is equivalent to <img src="https://tex.z-dn.net/?f=-4x%5E%7B-5%7D%20x%5E%7B0%7D" id="TexFormula1" title="-4x^{-
Ber [7]

The expression that is equivalent to the given expression is -4x^-5

<h3>How to determine which expression is equivalent to the given expression?</h3>

The expression is given as:

-4x^{-5} x^{0}

Rewrite properly as

-4x^-5x^0

Express as products

-4x^-5 * x^0

The value of x^0 is 1

So, we have:

-4x^-5 * 1

Evaluate the product

-4x^-5

Hence, the expression that is equivalent to the given expression is -4x^-5

Read more about equivalent expressions at:

brainly.com/question/2972832

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7 0
1 year ago
Solve the system by elimination<br><br> 3x-2y=3<br> 15x-4y=-3
stiv31 [10]

Answer:

x=-1

y=-3

Step-by-step explanation:

3x-2y=3(1)

5.(1) <=> 15x-10y=15 (2)

15x-4y=-3 (3)

(2)-(3) <=> -6y=18

4 0
2 years ago
Is the triangle obtuse, acute, equilateral or right?
Stells [14]

9514 1404 393

Answer:

  obtuse

Step-by-step explanation:

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

  b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

  b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

  \cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

  \cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

4 0
3 years ago
Read 2 more answers
X/7=x+14 / 5<br> Solve for X
elixir [45]

Answer:

x/7=x+14 / 5

Solve for X

Step-by-step explanation:

x/7=x+14 / 5

Solve for X

6 0
3 years ago
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