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3 years ago

How much is a 1 paint set if I spent 16.45 on 5 of the ?

Mathematics

1 answer:

Gemiola [76]3 years ago

7 0

Answer:

$3.29

Step-by-step explanation:

16.45 divided by 5 is 3.29

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Write the expression as a square of a monomial. a 81x^4

poizon [28]

Answer:

(9x²)²

Step-by-step explanation:

Given the expression 81x⁴, to write the expression as a square of a monomial, first we will assign a variable to the expression.

y = 81x⁴

Then we take the square root of both sides of the expression

√y = √81x⁴

y^½ = √81 × √x⁴

y^½ = 9x²

Squaring both sides of the resulting equation to get y back

(y^½)² = (9x²)²

y = (9x²)²

The expression as a square of a monomial is (9x²)²

7 0

3 years ago

Read 2 more answers

Find the minimum or maximum value of the function. What is the H? (Desmos)

beks73 [17]

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3( $x^{2}$ -4x)+16

=3( $x^{2}$ -4x+4-4)+16 (- For the balance of equation, and attention 1)

=3 $(x-2)^{2}$ -3*4+16

=3 $(x-2)^{2}$ +4

<h3>Attention:</h3>

1. $(a-b)^{2}=a^{2} -2ab+b^{2}$

2. The formula for the vertex form is y = $a(x-h)^{2}+k$ , the vertex is (h,k)

4 0

2 years ago

Offering around 20 points

givi [52]

Sarah

reason

she has the most consistent scores

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3 years ago

How many digits are written when 1000 to the power of 2015 is expressed as a numeral?

PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

$1000^{2015}$

We have to find the number of digits ,

So,

$1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}$

Since we know that

$10^n\text{ has n+1 number of digits }$

so,

$10^{6045}\text{ has 6046 number of digits }$

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0

3 years ago

Graph a line that contains the point (-5,-3) and has a slope of -2

Tpy6a [65]

Answer:

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Step-by-step explanation:

Graph (-5,-3) and use the slope, -2, to find another point. -2 can also be written as $-\frac{2}{1}$

$\frac{rise}{run} =\frac{-2}{1}$ and $\frac{rise}{run} =\frac{2}{-1}$ **

Use both. This works because either way, they will lie on the same line with the same slope. So, starting at (-5,-3), go down two points (-)* and to the left 1 (+)*, then, starting at (-5,-3) again, go up two points (+)* then to the right 1 point (-)*.

* If the number is negative, you either go down or to the right. If the number is positive, you go up and to the left.

**Rise over run refers to the change in the y-axis and the change in the x-axis: $\frac{rise}{run} =\frac{y-axis}{x-axis}$ . Only one number is negative because, if both were negative, that would make a positive number, but the slope is -2, not 2.