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34kurt
4 years ago
11

Paul was asked to use the elmination to find the solution to the system of linear equations

Mathematics
1 answer:
Georgia [21]4 years ago
3 0

Answer:9y-10y+1=-26

Step-by-step explanation:

Combine like terms and then keep your process going from there

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Can someone pls tell me if this is correct? For the properties, <3 and the bottom one too
saul85 [17]
1. Commutative property of multiplication This is because it represents a*b=b*a
2. Associative property of multiplication. Multiplication problems end with the same product no matter the order of factors.
3. Correct
4. Correct
5. Associative property of addition. Even though the grouping symbols are different, it is equivalent because you are adding all the terms together.
6. Correct

The last one should also be associative property since it applies every time you combine like terms.
Just a reminder: Distributive property is only when you multiply in the form of a(b+c)=ab+ac
7 0
3 years ago
Bailey has a teddy bear collection. 5 of the bears are pink this is 25% of all of her bears. How many total bears does she have
Elden [556K]

Answer:

Bailey has 20 total bears.

Step-by-step explanation:

She has 20 bears because 25% of 20 is 5. Or 5x4=20

6 0
4 years ago
Read 2 more answers
A dolphin's flipper, a bird's wing, and a cat's leg are considered to be homologous structures. Which of the following does this
Archy [21]

hope this helps

Step-by-step explanation:

They are considered homologous structures because they have a similar underlying anatomy.

3 0
3 years ago
Evaluate the expression
zheka24 [161]

Answer:

Step-by-step explanation:

x³ = 4³ = 4 * 4 * 4 = 64

4 0
3 years ago
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A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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