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ololo11 [35]
3 years ago
5

Help and explain//////////////////////////////////////////////

Mathematics
2 answers:
Paul [167]3 years ago
5 0

Answer:

5x - 3

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

= 2x + 4 + ( 3x - 7 )

= 5x - 3

erastovalidia [21]3 years ago
4 0

Answer:

(f + g)(x) = 5x - 3

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= 2x + 4 + 3x - 7 ← collect like terms

= 5x - 3

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What is the value of 7x²-10, when x = 6? please help me will mark<br> brainliest
vodka [1.7K]

Step-by-step explanation:

7(6^2)-10

=7×36-10

=252-10

242

3 0
3 years ago
WILL GIVE BRAINLIEST + 8 POINTS PLEASE HELP I NEED THIS QUESTION ANSWERED IN LESS THAN 25 MINUTES!!! EMERGENCY!!! Either Table A
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Answer:

its table a because all of the numbers are multiples of each other hope this helped

Step-by-step explanation:


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3 years ago
M/6-7=2/3 pls help plssssd
inna [77]

Step-by-step explanation:

M/6-7=2/3

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3 years ago
Nagrom the Dwarf Queen desires a tunnel through the mountain to connect her two wealthiest cities, Yram and Haras, which lie on
ladessa [460]

This question requires us to use the cosine rule:

a^2 = b^2 + c^2 - 2bc*cos(A),

where A is the included angle between sides b and c, and a is the side of the triangle opposite to the angle.

In the context of the question, a is the length of the tunnel (let's call this t), b is 6 km, c is 7 km and A is 29°.

Given the values in the question and those we defined, we can rewrite the equation for the cosine rule as:

t^2 = 6^2 + 7^2 - 2(6)(7)cos(29)

Now, evaluating this we get:

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6 0
4 years ago
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Jacqueline earned a commission of $200 for one week at work. her commission rate is 12% of the merchandise she sells. how much m
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For this case, the first thing we must do is define variables.

We have then:

m: original quantity of merchandise sold (in $)

We then have the following idea:

(original amount) (percent) = new amount

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We have then:

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  Answer:

The equation that solves the problem is:

m (0.12) = 200

The amount she sold is:

m = 1666.7

3 0
3 years ago
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