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3 years ago

If f(x) = 3 – 2x and g(x)=1/x+5, what is the value of (f/g)(8)? –169 –1 13 104

Mathematics

2 answers:

disa [49]3 years ago

5 0

Answer:

–169

Step-by-step explanation:

(f/g)(x) = ( 3 – 2x ) / (1 / x+5)

(f/g)(8) = (3 - 16)/(1/13)

(f/g)(8) = = -13 * 13

(f/g)(8) = - 169

Anettt [7]3 years ago

5 0

Answer: -169

Step-by-step explanation:

Given functions: $f(x)=3-2x\text{ and } g(x)=\dfrac{1}{x+5}$

The quotient function (f/g) is given by :_

$(f/g)(x)=\dfrac{f(x)}{g(x)}\\\\\Rightarrow (f/g)(x)=\dfrac{3-2x}{\dfrac{1}{x+5}}$

At x = 8 , we have

$(f/g)(8)=\dfrac{3-2(8)}{\dfrac{1}{8+5}}\\\\\Rightarrow\ (f/g)(8)=\dfrac{-13}{\dfrac{1}{13}}\\\\\Rightarrow\ (f/g)(8)=-13\times13=-169$

Hence, the value of $(f/g)(8)=-169$

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a) A dillation centered at the origin is defined by following operation:

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If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

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$C'(x,y) = \left(-3,-2\right)$

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$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

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$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

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