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Licemer1 [7]
2 years ago
15

Are the ratios 3:9 6:18 9:27 12:36 and 15:45 all proportional?

Mathematics
1 answer:
KatRina [158]2 years ago
5 0
Yes they are all proportional
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Factorise the following : ​
Free_Kalibri [48]

Answer:

(3x+4b)(a-2y)

Step-by-step explanation:

(3ax-6xy)+(8by-4ab)

3x(a-2y) -4b(-2y+a)

(3x+4b) (a-2y)

4 0
3 years ago
Read 2 more answers
Use the theoretical probability formula to solve the problem. Express the probability as a fraction
serg [7]

Answer:

c. 3 / 13

d. 2 / 13

Step-by-step explanation:

c.

A deck of cards has 52 cards. There are cards of 4 suits- Spades, Hearts, Diamonds and Clubs.

So, there are 52/4= 13 cards of each suit.

Among these 13 cards, there are 3 picture cards or face cards as they are called. These are the Jack, Queen and King cards.

So, the number of total picture cards = 4*3 = 12

the number of cards are 52

theoretical probability formula: P =  favorable events/  possible events

P = 12 / 52

P = 3 / 13

d.

there are four aces and four sevens in the deck

so favorable events = 4 + 4 = 8

possible eventas = 52

P = 8 / 52

P = 2 / 13

4 0
2 years ago
If angle 2 = 106 degrees, what is the measurement of angle 6 ? ( better explanation in picture )
Triss [41]

angle 2 and angle 6 are corresponding angles.

Since the lines crossed by the trnasversal are parallel, corresponding angles are congruent. (equal)

angle 6 = 106°

4 0
1 year ago
Please answer this correctly
iren2701 [21]

Answer:

10.71 yd

Step-by-step explanation:

First let's find the radius of the quarter circle.

area =\frac{1}{4} \pi {r}^{2} \\  7.065 = \frac{1}{4} *3.14 {r}^{2}  \\  \frac{7.065}{3.14}  = \frac{1}{4} * \frac{3.14 {r}^{2} }{3.14}  \\  9 =  {r}^{2}  \\  \sqrt{9}  = r \\ 3 yd= r

Now let's find the arc length of this quarter circle.

\frac{90}{360}  \times 2\pi \: r \\  \frac{1}{4}  \times 2 \times 3.14 \times 3 \\  =  \frac{9.42}{4}  \\  = 4.71yd \\

Now let's find the perimeterperimeter \\  = arc \:  \: length + radius + radius \\  = 4.71 + 3 + 3 \\  = 10.71yd

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

4 0
3 years ago
Read 2 more answers
6. rule (x,y) ---&gt; is the image similar to the original pre-image?
Artyom0805 [142]

Here, we want to check for the relationship between the image and its pre-image

The pre-image is (x,y)

The image is (3x,3y+5)

As we can see, the pre-image is not similar

This is because the transformation applied to the two values are not same

Thus, we have that;

No, the image is not similar to the pre-image as the translations applied to both coordinates are not same

The pre-image was transformed by dilating the x-coordinate of the pre-image by 3 units while the y-coordinate was transformed by dilating the y-coordinate of the pre-image by 3 and translating it upward by 5 units

3 0
1 year ago
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