Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
2(2x + 9) + 2(x) = 36
4x + 18 + 2x = 36
Combine like terms.
6x + 18 = 36
Subtract 18 from both sides.
6x = 18
Divide 6 on both sides.
x = 3
Hope this helps!
4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ
But 4 = 2² and 8 = 2³
4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ
2²⁽²ˣ ⁺ ⁵⁾ = (2³)³ˣ
Multiply out the powers, also since the
2⁴ˣ ⁺ ¹⁰ = 2⁹ˣ
Since the bases are the same, hence the powers are also the same.
4x + 10 = 9x
4x - 9x = -10
-5x = -10
x = -10/-5
x = 2
Hope this explains it.
Answer:
The slope is 5
Step-by-step explanation:
Slope is in place of the m hope this helps!
