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matrenka [14]
3 years ago
7

Please help with these two math problems 1. 7^x ÷ 7^y = 2. z^10x^y ÷ z^5 =

Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

  1.  7^(x-y)

  2. z^5x^y

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

__

1.

  \dfrac{7^x}{7^y}=\boxed{7^{x-y}}

__

2.

  \dfrac{z^{10}x^y}{z^5}=x^yz^{10-5}=\boxed{z^5x^y}

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Westkost [7]

Answer:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean \mu is given by this formula:

\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}

The confidence level on this case is 0.9 and the significance \alpha=1-0.9=0.1

The confidence interval calculated on this case is 60.128 \leq \mu \leq 69.397

The margin of error for this confidence interval is given by:

ME =t_{\alpha/2} \frac{s}{\sqrt{n}}

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

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Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

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3 years ago
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Answer:

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