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3 years ago

Please help with these two math problems 1. 7^x ÷ 7^y = 2. z^10x^y ÷ z^5 =

Mathematics

1 answer:

IceJOKER [234]3 years ago

8 0

Answer:

1. 7^(x-y)

2. z^5x^y

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{7^x}{7^y}=\boxed{7^{x-y}}$

$\dfrac{z^{10}x^y}{z^5}=x^yz^{10-5}=\boxed{z^5x^y}$

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5/2.35 = x/12 what does x=

postnew [5]

Answer:

$x = \frac{60}{2.35}$ or $x = 25.531...$

Step-by-step explanation:

Step 1: Cross Multiply

$\frac{5}{2.35} = \frac{x}{12}$

$5(12) = 2.35(x)$

$60 = 2.35x$

Step 2: Divide both sides by 2.35

$60 / 2.35 = 2.35x / 2.35$

$x = \frac{60}{2.35}$ or $x = 25.531...$

Answer: $x = \frac{60}{2.35}$ or $x = 25.531...$

5 0

3 years ago

Let f(x)=-5x-4 and g(x)=6x-7. find f(x) + g(x)

DIA [1.3K]

F(x) = -5x - 4

g(x) = 6x - 7

f(x) + g(x) = (-5x-4) + (6x-7)

f(x) + g(x) = x - 11

3 0

3 years ago

Read 2 more answers

Which is least 1.3 1 1/3 or 1.34

Evgesh-ka [11]

1.3 is the least because ur supposed to add a zero so they can all be the same place value

5 0

3 years ago

Please help write the equation of the line.

AfilCa [17]

Answer:

x -2y -2=0

Step-by-step explanation:

using the formula, m= ( Y2 - Y1)/( X2-X1)

the gradient is found. the coordinates chosen are (2,0) and ( 0,-1)

the equation of the line is obtained using the formula

y -y1= m(x -x1)

3 0

2 years ago

Brielle and Joshua are running a half marathon race, which is 13.1 miles long. It takes Brielle 10 minutes to run 1.25 miles and

CaHeK987 [17]

Answer: Brielle will run the marathon faster.

Brielle = 104.8 minutes

Joshua = 157.2 minutes

Step-by-step explanation:

Speed rate = distance /time

Brielle = 1.25 /10 = 0.125 miles per minute

Joshua = 1.5/18 = 0.083333 =1/12 miles per minute

Since 0.125 (Brielle) > 1/12 (Joshua)

Brielle will run the marathon faster.

To calculate the time that takes each one to run the entire race (13.1 miles)

Time= distance / speed

Brielle = 13.1 /0.125 = 104.8 minutes
Joshua = 13.1 / (1/12)= 157.2 minutes

Feel free to ask for more if needed or if you did not understand something.

8 0

3 years ago