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alexandr1967 [171]
3 years ago
10

Determine the equation of the graph (picture provided).

Mathematics
2 answers:
Margaret [11]3 years ago
7 0
I think the answer is c

alina1380 [7]3 years ago
3 0

Answer:

Y=1/2 csc(x)

Step-by-step explanation:

Edg 2020

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Find y when x = 3 of the equation for y=2x+12
ser-zykov [4K]

Answer:

y = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

y = 2x + 12

x = 3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                y = 2(3) + 12
  2. Multiply:                                                                                                           y = 6 + 12
  3. Add:                                                                                                                 y = 18
3 0
3 years ago
Read 2 more answers
The tables below show the values of y corresponding to different values of x: Table A x 3 3 2 y 1 0 0 Table B x 3 5 5 y −2 2 −2
andriy [413]

Answer:

is it possable you can show the graph

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Fill in the blank with the correct response.
I am Lyosha [343]

Answer:

In a standard normal distribution

95% of the data is within 2 standard deviations of the mean.

have a nice day! (^o^)

6 0
2 years ago
3pr - 4ps + 12qs - 9qr = ?​
aleksklad [387]
It cannot be simplified more than that. hope this helps!
4 0
3 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;upstream&100&b-c&5\\&#10;downstream&100&b+c&2&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;100=(b-c)5\\&#10;\qquad \frac{100}{5}=b-c\\&#10;\qquad 20=b-c\\&#10;\qquad 20+c=\boxed{b}\\&#10;100=(b+c)2\\&#10;\qquad 50=b+c\\&#10;\qquad 50=\boxed{20+c}+c&#10;\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
2 years ago
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