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2 years ago

State the two transformations in the attachment below please be specific!! HELP QUICK!!

Mathematics

1 answer:

Sergio039 [100]2 years ago

7 0

Answer:

Translate 3 to the right and 12 down.

Dilate using point C and a scale factor of 3

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The density of copper is 8.94 g/cm^3. What is the mass of a rectangular sheet of copper: 10 cm wide, 45 cm long, and 0.2 cm thic

Brums [2.3K]

Density = mass/volume

Let mass=x

8.94= x/(10*45*.2)

X=8.94*90
Mass=804.6 g

Hope this helped :)

4 0

1 year ago

Answer by formula please

Ierofanga [76]

Answer:

Step-by-step explanation:

I honestly have no idea what you mean by answer by formula, but I'm going to give it my best. I began by squaring both sides to get:

(a² - b²) tan²θ = b² and then distributed to get:

a² tan²θ - b² tan²θ = b² and then got the b terms on the side to get:

a² tan²θ = b² + b² tan²θ and then changed the tans to sin/cos to get:

$\frac{a^2sin^2\theta}{cos^2\theta}=b^2+\frac{b^2sin^2\theta}{cos^2\theta}$ and isolated the sin-squared on the left to get:

$a^2sin^2\theta=cos^2\theta(b^2+\frac{b^2sin^2\theta}{cos^2\theta})$ and distributed to get:

*** $a^2sin^2\theta=b^2cos^2\theta+b^2sin^2\theta$ *** and factored the right side to get:

$a^2sin^2\theta=b^2(sin^2\theta+cos^2\theta)$ and utilized a trig Pythagorean identity to get:

$a^2sin^2\theta=b^2(1)$ and then solved for sinθ in the following way:

$sin^2\theta=\frac{b^2}{a^2}$ so

$sin\theta=\frac{b}{a}$ This, along with the *** expression above will be important. I'm picking up at the *** to solve for cosθ:

$a^2sin^2\theta=b^2cos^2\theta+b^2sin^2\theta$ and get the cos²θ alone on the right by subtracting to get:

$a^2sin^2\theta-b^2sin^2\theta=b^2cos^2\theta$ and divide by b² to get:

$\frac{a^2sin^2\theta}{b^2}-sin^2\theta=cos^2\theta$ and factor on the left to get:

$sin^2\theta(\frac{a^2}{b^2}-1)=cos^2\theta$ and take the square root of both sides to get:

$\sqrt{sin^2\theta(\frac{a^2}{b^2}-1) }=cos\theta$ and simplify to get:

$\frac{sin\theta}{b}\sqrt{a^2-b^2}=cos\theta$ and go back to the identity we found for sinθ and sub it in to get:

$\frac{\frac{b}{a} }{b}\sqrt{a^2-b^2}=cos\theta$ and simplifying a bit gives us:

$\frac{1}{a}\sqrt{a^2-b^2}=cos\theta$

That's my spin on things....not sure if it's what you were looking for. If not.....YIKES

5 0

2 years ago

What is the value of x?

larisa86 [58]

Answer:

it is 10

Step-by-step

4 0

3 years ago

Denise bought 12 slices of cheese at he deli. The total weight of cheese she bought was 1/4 pound What is the weight of each sli

antiseptic1488 [7]

1/3 ounce - 1/4 pound is 4 ounces and then you just divide by 12, resulting in .3333333333 or in other words, 1/3

4 0

3 years ago

2. Harold is interested in selling his father's baseball card

Vitek1552 [10]

Answer:

$58.50

Step-by-step explanation:

The fee will be equal to the percentage times the selling price. Converting the percentage to a decimal, we get 18%=0.18

Multiplying this by the selling price:

325*0.18=58.5

4 0

3 years ago