Answer:
Shorter leg = 2.5 ft.
Longer leg = 6.5 ft.
Step-by-step explanation:
a^2 + b^2 = c^2
Because the hypotenuse = 7 ft, a^2 + b^2 = 49
To represent the two legs, we can use x and x+4.
x^2 + (x+4)^2 = 49
Simplifying this equation using FOIL gives us 2x^2 + 8x - 33 = 0.
Then, using the quadratic formula, we find that x = 2.5.
Thus, the shorter leg is 2.5 ft. and, when 4 is added, the longer leg is 6.5 ft.
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Answer:
v = m/d
Step-by-step explanation:
d = m/v
Multiply each side by v
d*v = m/v * v
dv = m
Now divide each side by d
dv/d = m/d
v = m/d
Its a repeating decimal 0.22222222222222222222222
<span>y=
-0.000475x^2 + 0.851x
How high above is the
river bridge (the top of the arch)?
You have to find the vertex of of the parabole: the y-coordinate is the highest point.
Remember that the x-coordinate of the vertex of a parabole is at - b / 2a.
That is x = - 0.851 / [ 2(-0.000475) = 895.79
The corresponden y is y = </span><span>-0.000475(895.79)^2 + 0.851(895.79) = 381.16 feet above the river.
How long is section of bridge above
the arch?
The section of the brige is equal to the difference of the two roots
Roots: </span><span>y=
-0.000475x^2 + 0.851x = 0
=> x( - 0.000475x + 0.851) = 0
=> x = 0 and x = 0.851 / 0.000475 = 1791.58
Then the section is 1791.58 feet long.
Therefore, the answer is the option </span><span>D)The bridge is about 381.16 ft. above the river, and the length of the bridge above the arch is about 1,791.58 ft
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