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Vitek1552 [10]
3 years ago
12

A rectangular Corn Hole area at the recreation center has a width of 5 feet and a length of 10 feet. If a uniform amount is adde

d to each side, the area is increased to 84 square feet. What is the amount added to each
sidhttps://s3.amazonaws.com/algebranation/testyourself_uploads/MAFS7/7.043.pnge?
Mathematics
2 answers:
almond37 [142]3 years ago
5 0
1. The formula for calculate the area of a rectangle, is:
 
 A=LxW
 
 A is the area of the rectangle
 L is the length of the rectangle.
 W is the widht of the rectangle

2. You have that:
 
 -The<span> rectangular Corn Hole area has a width of 5 feet and a length of 10 feet, so:
 
 L1=10 feet
 W1=5 feet
 
 - When</span> a uniform amount is added to each side (x), the area is increased to 84 feet². Then, you have a different length (L2) and a different width (W2):
 
 3. The new length is:<span> 
 
 L2=L1+x+x
 L2=L1+2x
 L2=10+2x
 
 4. The new width is:
 
 W2=W1+x+x
 W2=W1+2x
 W2=5+2x
 
 5. The new area is:
 
 A2=84 feet</span>²<span>
 
 6. Then, you have:
 
 A=LxW
 84</span>=(10+2x)(<span>5+2x)
 
 7. When you apply the distributive property, you obtain a quadratic equation:
 
 4x</span>²+30x-34=0
<span> 
 8. You can solve with by applyin the quadratic formula: 
 
 x=(-b±√(b^2-4ac))/2a
 
 a=4
 b=30
 c=-34
 
 9. Then, the answer is:
 
 x=1 feet
</span><span> 
</span>
bekas [8.4K]3 years ago
5 0

Answer:

I can't believe this guy above me has a verified answer and it is wrong.... anyway the true answer to this is 2. I checked it myself when I put 1 as the answer and got this question wrong, and it showed me the correct answer is 2 so don't believe the verified answer.

Step-by-step explanation:

Review Question #7:

The answer to this question is 2ft, not 1ft.

This is because:

So the width of the second rectangle can be represented by 10+2x, and the length of the second rectangle can be represented by 5+2x. Lets make 2x equal y to make things easier though. Because the product of both 10+2x and 5+2x is 84 square feet, we must multiply the two equations together first.

(10+y)(5+y)=84

This then equals:

50+10y+5y+y^2=84

Then add the like terms:

y^2+15y+50=84

Then set the equation to zero by subtracting 84 from both sides:

y^2+15y-34=0

From that, you can use the box method, or any method to get:

(y+17)=0 and (y-2)=0

Which would then simplify to:

y=-17 and y=2

However, we substituted y for 2x, so plug 2x into y:

2x=-17 and 2x=2

Then simplify from here:

x=-17/2 and x=1

The answer cannot be negative, so that means the answer is x=1, however, even though this is true, the answer is that 2ft was added to EACH SIDE, because the question was asking for what amount was added to each side.

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I need a little help here please
erma4kov [3.2K]

Answer:

Plot points at (0,1) and (-3,3) and draw a line going through both points.

Step-by-step explanation:

Let's start by graphing the y intercept.

y=mx+b

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3 0
2 years ago
Suppose j varies jointly with g and​ v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.
vladimir2022 [97]

Answer:

j=12

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form j = kgv

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

2 = k(4)(3)

2 = 12k

k=\frac{1}{6}

The equation is equal to

j=\frac{1}{6}gv

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

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3 0
3 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
Plz answer and give an explanation to the answer.
VladimirAG [237]
#29 is 1x - 6 and you had to divide the two numbers
5 0
3 years ago
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