Answer: Insufficient Information
The probability of selecting a red ball, a blue ball or a white ball is unknown.
Step-by-step explanation:
The probability of selecting a red ball, a blue ball or a white ball is unknown.
There could be 13 red balls, 1 blue ball and 11 white balls in the bag. There could be 3 red balls, 2 blue balls and 20 white balls in the bag. It is impossible to say with the information given have even numbers on them. The same thing applies to the number of balls with numbers or even numbers on them. The question does not specify how many white balls have each number on them.
Answer:
g(x) = f(x+1) + 1
Step-by-step explanation:
Since the graph is only moved you don't have to worry about the slope.
To move the graph to the left you add to the x and in this case, it only moved 1 over.
to move the graph up you add to the whole function and in this case, it only moved up 1.
There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
Step-by-step explanation:
Given :
1- cosA = 1/2
or, CosA = 1 -1/2
Therefore ; CosA = 1/2 = b/h
According to the Pythagoras theorem,
P = root under h^2 - b^2
= root under (2)^2 - (1)^2
= root under 4 -1
= root 3
Again,
SinA = P/h
= root 3 / 2
It is 7.5, think like 100÷4
