Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2
Answer:
the answer is 25 okay so you need to subtract 4 from 29 you end up with 25
Answer: B. same distance
There is the same distance between the point on the preimage to the center of rotation and that of the distance from the corresponding point on the image to the center of rotation. There is change in the distance of the two.
<h3>
Answer: First choice. angle C = angle Z</h3>
Explanation:
AC = XZ shows that the horizontal pieces are congruent. This is the "S" of "ASA" as it stands for the pair of congruent sides. We are also given angle A = angle X. This is one of the "A"s in "ASA" as it stands for pair of congruent angles.
What we're missing is the other pair of angles. We must pick C and Z because they help sandwich the two sides mentioned above. ASA has the two angles surrounding the sides; or the sides are between the angles. We can't pick B and Y, unless we were doing AAS which is a similar related idea. The order matters when it comes to ASA and AAS. However, AAS is the same as SAA.
For this case we have the following function:
we have:
Where:
By definition, the discriminant of a quadratic equation is given by:
Two different real roots
Two equal real roots
: Two different complex roots
Substituting the values we have:
We have two equal real roots.
To find the intersections with the x axis, we do 
We apply the quadratic formula:
Substituting the values we have:
The intersection with the x axis is
Answer:
The intersection with the x axis is
