Question

There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Academic Year Chemistry majors non-Chemistry majors Freshmen 15 15 Sophomores 13 9 Juniors 2 10 Seniors 12 16 What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

Answer 1

Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

$P(A) = \frac{9}{92}$

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

$P(B) = \frac{10}{91}$

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

$P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108$

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.